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The closed metallic cylinder has its base diameter 56 cm and it is 2.25 M height find the cost of the metal used to make it if it cost 80 rupees per square metre

Posted by Veena Rai 6 years, 3 months ago

CBSE > Class 08 > Mathematics

2 answers

Sia ? 6 years, 3 months ago

Radius={tex}\frac {Diameter}{2}{/tex}={tex}\frac {56}{2}=28{/tex}
Height =2.25m
We have to convert radius in m
Therefore, {tex}\frac {28}{100}m=0.28m{/tex}
T.S.A = 2πr (r + h) = 2{tex}\times{/tex}{tex}\frac {22}{7}{/tex}{tex}\times{/tex}0.28{tex}\times{/tex}(0.28+2.25)=1.76{tex}\times{/tex}2.53m²=4.4528m²
Cost of metal = (4.4528{tex}\times{/tex}80) = 356.22

0Thank You

Yogita Ingle 6 years, 3 months ago

Radius=Diameter/2 = 56/2cm = 28cm
Height = 2.25m
We have to convert radius in m
Therefore, 28/100m = 0.28m
T.S.A = 2πr (r+h) =2*22/7*0.28*(0.28+2.25) =1.76*2.53m²=4.4528m²
Cost of metal=₹ (4.4528*80)= ₹ 356.22

1Thank You

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