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Sia ? 6 years, 4 months ago
We know that, Pressure at the surface of earth = 76 cm = 76 {tex}\times{/tex} 13.6 cm Hg
= 1033.6 cm of Hg
= 10.3 m of Hg
Now, Presssure at 100 m depth = 100 m + 10.3 m = 110.3 m of Hg
So, {tex}p_1 = 10.3,p_2 = 110.3,V_1 = V, V_2=?{/tex}
At constant temperature,
{tex}p_{1} V_{1}(\text { at surface }) = p_2 V_2 (\text{at 100 m depth}){/tex}
{tex}\Rightarrow 10.3\times V= 110.3\times V_2{/tex}
{tex}\Rightarrow V_{2}=0.093 \mathrm{V}\\ \Rightarrow V_{2}=9.3 \% \text { of } V{/tex}
0Thank You