By which smallest natural number 9408 …

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Posted by Prince Prajapati 6 years, 4 months ago
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Yogita Ingle 6 years, 4 months ago
To find the smallest number by which 9408 must be divided so that the quotient is a perfect square, we have to find the prime factors of 9408.
9408 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 7 × 7
Prime factors of 9408 are 2, 2, 2, 2, 2, 2. 3, 7, 7
Out of the prime factors of 9408, only 3 is without pair.
So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.
9408/3 = 3136
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