Two complementary angles difference by 12°,find …
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Sia ? 6 years, 4 months ago
Let the measures of two complementary angles be x° and y° (x° > y°).
Since among the angles x° and y° one is complementary angles, therefore
x° + y° = 90° . . . (1) . . [By definition of complementary angles]
Since the difference in the measures of x° and y° (x° > y°) is 12°,
Therefore, x° – y° = 12° . . . (2)
Adding equation (1) and (2)
2x° = 102°
{tex}\Rightarrow{/tex} x° = {tex}\frac{102^{\circ}}{2}{/tex} = {tex}51^{o}{/tex}
Subtracting equation (2) from equation (1),
{tex}\Rightarrow{/tex} y° = {tex}\frac{78^{\circ}}{2}{/tex}= 39o
Hence, the measures of the angles are 51° and 39°.
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