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Can plz anyone tell me the ans of 31 st question of exercise of chapter 2? Plzzzzz???

Posted by Susmita Mandal 6 years, 5 months ago

CBSE > Class 11 > Chemistry

4 answers

Susmita Mandal 6 years, 5 months ago

The electronic configuration is wrong.....check it out Unnati.....plz

Unnati Pragya 6 years, 5 months ago

A) Total no. of electron in an atom for a value of n=2n^2 For n= 4 Total number of electron=2(4)^2 The given element has a fully filled orbital as 1s^2 2s^2 2p^ 6 3s^2 3p^6 4s^2 3d^10 Hence all the electron are paired Number of electron (having n= 4 nd m ↓s =-1/2) =16 B) n= 3, l =0 indicate that the electron are present in the 3S orbital Therefore the number of electron having an equal to 3 and l equal to zero is 2

Nishant Yadav 6 years, 5 months ago

Unknown

Susmita Mandal 6 years, 5 months ago

I think it's wrong in this app

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