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Q.Determine the empirical formula of an …

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Q.Determine the empirical formula of an oxide of iron which has 69.9% Fe and 30.1% of Dioxygen by mass????????
  • 1 answers

Sia ? 6 years, 8 months ago

The following table illustrates different steps followed in determination of empirical formula of an oxide of iron using the given data - 

<th scope="row">Element</th> <th scope="col">Symbol</th> <th scope="col">% by mass</th> <th scope="col">Atomic mass</th> <th scope="col">Mols of the element
Fe 69.9 55.85 {tex} \frac{69.9}{55.85}{/tex}= 1.25 {tex}\frac{1.25}{1.25}{/tex}= 1 2
O 30.1 16.00 {tex}\frac{30.1}{16.00}{/tex}= 1.88 {tex}\frac{1.88}{1.25}{/tex}= 1.5 3

Thus it is concluded that the oxide contains -
2 atoms of Fe  
&, 3 atoms of O 
hence, the ratio of atoms  in  the oxide of iron  
= 2 : 3
{tex}\therefore{/tex} Empirical formula - Fe2O3

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