The diameter of the zinc atom …

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Sia ? 6 years, 5 months ago
Diameter of zinc atom = 260 pm
{tex}\therefore{/tex} No. of zinc atoms placed side by side = {tex}\frac{\left(1.6 \times 10^{10} \mathrm{pm}\right)}{(260 \mathrm{pm})}{/tex}= 6.154 {tex}\times{/tex} 107
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