Why nh3 has more dipole moment …
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Posted by Ajay Gusain 7 years, 7 months ago
- 2 answers
Naveen Sharma 7 years, 7 months ago
In both molecules i.e., NH3 and NF3, the central atom (N) has a lone pair electron and there are three bond pairs. Hence, both molecules have a pyramidal shape. Since fluorine is more electronegative than hydrogen, it is expected that the net dipole moment of NF3 is greater than NH3. However, the net dipole moment of NH3 (1.46 D) is greater than that of NF3 (0.24 D).
Since in case of NF3 , fluorine is more electronegative than nitrogen, so it will attract the shared pair of electron towards itself from nitrogen. As a result dipole due to all F is in opposite direction to the resultant dipole due to N-F bonds,therefore the net dipole decreases.
In NH3, Nitrogen is more electronegative than H, so it will attract the shared pair of electrons towards itself.As a result dipole due to Nitrogen is in same direction as the resultant dipole moment due to N-H bond& hence the net dipole increases.
Hence, the net dipole moment of NF3 is less than that of NH3.
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Amar Kumar 7 years, 7 months ago
Dipole moment of NH3 is higher than NF3 molecule. This is due to the fact that dipole moment is a vector quantity and hence resultant dipole moment in a molecule will depend upon the direction of dipole moments of individual bonds. Nitrogen has a lone pair of electrons and is more electronegative than hydrogen. So, in case of NH3, the orbital moment due to the lone pair of electrons on nitrogen is in the direction of lone pair of electrons is in the same direction of the 3 N-H dipoles. Thus, the molecule has a net dipole moment and it is polar.
In NF3, Florine being more electronegative than Nitrogen pulls the shared pair of electrons of the N-F bonds towards itself. Because of this, the orbital moment due to lone pair of electrons and the resultant dipole moment of 3 N-F bonds point in the opposite directions to that of lone pair of electrons. This lowers the dipole moment of NF3.
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