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5(t-4)+5(t+2)-7(t-1)=0

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5(t-4)+5(t+2)-7(t-1)=0

Posted by Dinesh Waghchoure 6 years, 5 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 6 years, 5 months ago

5(t-4)+5(t+2)-7(t-1)=0
5t - 20 + 5t + 10 - 7t + 7 = 0
5t + 5t - 7t - 20 +10 + 7 = 0
3t - 3 = 0
3t = 3
t = 3/3
t = 1

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