How many g of Na2Co3 shold …
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Sia ? 6 years, 5 months ago
1000 cm3 of 0.15 M Na2CO3 contains Na2CO3 = 0.15 mol
100 cm3 of 0.15 M Na2CO3 Will contain Na2CO3 = {tex}\frac { 0.15 } { 1000 } \times 100 = 0.015 \mathrm { mol }{/tex}
Molar mass of Na2CO3 = 2 {tex}\times{/tex} Na +1 {tex}\times{/tex} C +3 {tex}\times{/tex}O =2 {tex}\times{/tex}23 +1 {tex}\times{/tex} 12 + 3 {tex}\times{/tex} 16= 46 + 12 + 48 =106 g mol-1
Therefore, Mass of Na2CO3 =Number of mole of Na2CO3 {tex}\times{/tex} Molar mass of Na2CO3 = 0.015 mole {tex}\times{/tex}106 g/mol = 1.59 g.
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