One one of the two digit …

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Sia ? 6 years, 8 months ago
Let the digit at unit place be x
The digit at tens place = 3x
So, the number is = {tex} = 10 \times 3x + x{/tex}
= 30x + x
= 31x
On interchanging the digits,
The digit at unit place = 3x
and the digit at tens place = x
Now number = 10x + 3x
= 13x
According to the question,
31x + 13x = 88
44x = 88
{tex}x = \frac{{88}}{{44}}{/tex}
{tex}\therefore x = 2{/tex}
So, the digit at unit place is 2 and the digit at tens place {tex} = 3 \times 2 = 6{/tex}
Hence, the original number is 62.
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