sum of the digits of a …
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Posted by Amith Keshav 6 years, 5 months ago
- 2 answers
Gaurav Seth 6 years, 5 months ago
Let the digit in units place = x
The digit in tens place = 3x
The number is 10(3x) + x = 31x
Digits are interchanged
Digit in units place = 3x
Digit in tens place = x
The new number= 10(x) + 3x = 13x
Sum of these two numbers = 88
31x + 13x = 88
44x = 88
x = 2
3x = 6
The original number is 62
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Gaurav Seth 6 years, 5 months ago
Let the digits be x and y.
Then, x+y = 9
the original number is 10x+y.
On reversing, we get the new number as 10y+x
The new number is greater than the old number by 27, i.e.
(10y+x) - (10x+y) = 27
or 9y-9x = 27, or y-x = 3
and x+y = 9
Adding the two equations, we get 2y = 12 or y = 6.
Thus, x = 3.
Therefore, the original number is 36.
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