1) the energy associated with the …
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Sia ? 6 years, 5 months ago
{tex}\frac{E_{1}}{E_{2}}=\left(\frac{n_{2}}{n_{1}}\right)^{2}{/tex}
According to available data: n1 = 1,E1 = - 2.17 {tex}\times{/tex} 10-18 J atom-1, n2 = 5
{tex}\therefore{/tex} {tex}\frac{\left(-2.17 \times 10^{-18} \mathrm{J} \text { atom }^{-1}\right)}{\mathrm{E}_{2}}=\left(\frac{5}{1}\right)^{2}{/tex} = 255
E5 = {tex}\frac{\left(-2.17 \times 10^{-18} \mathrm{J} \text { atom }^{-1}\right)}{25}{/tex}= -8.77 {tex}\times{/tex} 10-20 J
r5 = 0.529 {tex}\times{/tex} (5)2 = 13.225 {tex}\stackrel{\circ}{A}{/tex} = 1.3225 nm
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