Calculate the shortest wavelength in helium …
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Sia ? 6 years, 5 months ago
Lyman series, n = 2, 3, 4... to n= 1
For short wavelength, n ={tex}\infty{/tex} to n = 1
we know that ,
{tex}E = \frac { 12375 } { \lambda ( \mathop A\limits_{}^o ) } = \frac { 12375 } { 9134 } \mathrm { eV } = 13.54 \mathrm { eV }{/tex}
Energy of nth orbit, E = 13.54/n2
So, energy of n = 1, energy level = 13.54eV
Energy of n = 2, energy level= 13.54/22 = 3.387 eV
So, short wavelength of Balmer series = {tex}\frac { 12375 } { 3.387 }{/tex} = 3653 {tex}\mathop A\limits_{}^o {/tex}
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