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A shample of Naoh weighting 0.38gm …

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A shample of Naoh weighting 0.38gm is dissolve in water and the solution os made to 50.0ml in a volumetric flask. What is the molarity of the resulting solution

Posted by Mohd Shoil 6 years, 6 months ago

CBSE > Class 11 > Chemistry

1 answers

Ranjeet Kumar 6 years, 6 months ago

Molar mass of NaOH = 40g/mol Moles of NaOH in solution(n) = 0.38g ÷ 40g/mol = 0.01 mol Volume in litres V(L) = 50/1000 L Molarity = n/ V(L) =(0.01/ 50)×1000 mol/L = 0.2 mol/L

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