In a ∆ABC,AB=15cm,BC=13cm and AC=14cm.Find the …
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Yogita Ingle 6 years, 6 months ago
In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm.
By Heron's formula ,
S = ( A + B + C ) / 2
S = ( 15 + 13 + 14 ) / 2
S = 42 / 2
S = 21
Now, area of triangle
= √S (S–A) (S–B) (S–C)
= √21 (21–15) (21–13) (21–14)
= √21 (6) (8) (7)
= √7056
= 84 cm2
Again,area of triangle = 1/2×base×altitude=84 cm2
1/2×14×altitude = 84
7 × altitude=84
altitude = 84/7
Altitude = 12cm
Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.
2Thank You