Calculate energy of one mole of …
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Sia ? 6 years, 6 months ago
Energy (E) of one photon = E = hv
where h = 6.626 {tex}\times{/tex} 10-34 Js.
{tex}\nu{/tex} = 5 {tex}\times{/tex} 1014 s-1
{tex}\therefore E = \left( 6.626 \times 10 ^ { - 34 } \times 5 \times 10 ^ { 14 } \right){/tex}
{tex}= 3.313 \times 10 ^ { - 19 } J{/tex}
Energy of 1 mole of photon{tex}= \left( 3.313 \times 10 ^ { - 19 } J \right) \times \left( 6.022 \times 10 ^ { 23 } \mathrm { mol } ^ { - 1 } \right){/tex}= 1995.1 kJmol-1
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