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Sia ? 6 years, 5 months ago
Let the number be x.
Then, according to the question, {tex}\left( {x - \frac{5}{2}} \right)8 = 3x{/tex}
∴ {tex}8x - \frac{5}{2} \times 8 = 3x{/tex}
∴ 8x – 20 = 3x
∴ 8x – 3x = 20 . . . . [Transposing 3x to L.H.S. and –20 to R.H.S.]
∴ 5x = 20
∴ {tex}x = \frac{{20}}{5}{/tex} . . . . [Dividing both sides by 5]
∴ x = 4 hence, the required number is 4.
Verification
{tex}\left( {4 - \frac{5}{2}} \right)8 = \frac{{8 - 5}}{2} \times 8 = \frac{3}{2} \times 8 = 3 \times 4 = 12{/tex}
3x = 3 × 4 = 12 hence, the result is verified.
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