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Kamal borrowed 26400 from a bank …

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Kamal borrowed 26400 from a bank to buy a scooter at a rate of 15% p.a compounded yearly. what amount will she pay at the end of 2 years and 4 months to clear the loan
  • 1 answers

Sia ? 6 years, 5 months ago

P = Rs. 26400
R = 15% p.a.
n = 2 years
{tex}\therefore A = P{\left( {1 + \frac{R}{{100}}} \right)^n} = 26400{\left( {1 + \frac{{15}}{{100}}} \right)^2}{/tex}
{tex} = 26400{\left( {1 + \frac{3}{{20}}} \right)^2} = 26400{\left( {\frac{{23}}{{20}}} \right)^2}{/tex}
{tex} = 26400 \times \frac{{23}}{{20}} \times \frac{{23}}{{20}} = Rs.34914{/tex}
S.I. on Rs. 34914 at 15% p.a. for 4 months
{tex} = \frac{{34914 \times 15 \times 1}}{{3 \times 100}}{/tex}
= Rs. 1745.70
{tex}\therefore {/tex} Required amount = Rs. 34914 + Rs. 1745.70
= Rs. 36659.70
Hence, the amount that Kamala will pay is Rs. 36659.70.

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