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A road roller takes 750 complete …

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A road roller takes 750 complete rotations to move once over to level a road .Find the area of the road roller is 84cm and length is 1 m

    • Posted by Aishwarya Lakshmi 6 years, 6 months ago

    CBSE > Class 08 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    Diameter of the road roller = 84 cm
    {tex}\therefore{/tex} Radius (r) of the road roller {tex} = \frac{{84}}{2}{/tex}cm = 42 cm
    Length (h) of the road roller = 1m = 100 cm
    {tex}\therefore{/tex} Lateral surface area of the road roller {tex} = 2\pi rh{/tex}
    {tex} = 2 \times \frac{{22}}{7} \times 42 \times 100{/tex}
    = 26400 cm2
    {tex}\therefore{/tex} Area of the road covered in 1 complete revolution = 26400 cm2
    {tex}\therefore{/tex} Area of the road covered in 750 complete revolutions
    = 26400 cm2 {tex}\times{/tex} 750 cm2
    = 19800000 cm2
    {tex} = \frac{{19800000}}{{100 \times 100}}{m^2}{/tex}
    = 1980 m2

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