KE = 1/2 mv²

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Meghna Thapar 6 years, 1 month ago
Consider an object of mass, m moving with a uniform velocity, u. Let it now be displaced through a distance s when a constant force, F acts on it in the direction of its displacement. Work done, W is F s. The work done on the object will cause a change in its velocity. Let its velocity change from u to v. Let a be the acceleration produced. The relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement,
s is v2 – u2 = 2a s
This gives
s = v2 – u2 /2a
Thus, work done by force F
= m a x (v2 – u2 /2a )
Or ½ m (v2 – u2)
If the object is starting from its stationary position, that is, u = 0, then
W = ½ mv2
Therefore, work done is equal to the change in the kinetic energy of an object.
If u = 0, the work done will be ½ mv2.
Thus, the kinetic energy possessed by an object of mass, m and moving with a uniform
velocity, v is
Ek = ½ mv2
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