If the concentration of glucose(C6 H12 O6) in …
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Payal Singh 8 years, 7 months ago
Solution
Concentration of glucose in blood = 0.9g/L Number of moles of glucose = {tex}{0.9\over 180 } = 0.005\space moles{/tex}
Volume of solution = 1 litre
Hence, Molarity = {tex}Number \space of \space moles \over Volume \space of \space solution \space in\space litres{/tex} = {tex}0.005 \over 1 {/tex}= 0.005M
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