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The diameter of shephr is decrease …

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The diameter of shephr is decrease by 20 percent by what per sent does it's curved surface area decrease

    • Posted by Anjali Sinha 5 years, 1 month ago

    Entrance Exam > JEE main > Mathematics
    • 1 answers

    Pulkit Bansal 5 years, 1 month ago

    Diameter of sphere=d New sphere=D So, D=d-20% of d D=d-20d/100 D=d-4d/20 D=4d/5 S.A. of old sphere= 4π(d/2)^2 = πd^2 S.A of new sphere= 4π[(4d/5)/2]^2 = (16πd^2)/25 % of area decrease = 【{πd^2 - (16πd^2)/25}/πd^2】×100 = 36%

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