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An object is thrown upward to …

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An object is thrown upward to a certain height with a velocity of 3 m/s. If the time required to reach the height is 5s. Calculte the height at which it was thrown(hint: (g=10m/s2) (use second equation of motion)
  • 3 answers

Priyanshu Sagar 7 years, 1 month ago

Here is the answer of your question an object is thrown upward then ,final velocity (v)=0 ,initial velocity (u)=3m/s, time (t)=5sec. Height (s)=? To find S, we find acceleration V=u+at 0=3+a×5 -3=5a -3/5=a using second equation of motion S=ut+1/2×a×t square S=3×5+1/2×-3/5×5 square S=15-3/10×25 S=15-15/2 S=30-15÷2 S=15/2 S=7.5m

Ashish Bhadouria 7 years, 1 month ago

45 m

Priyanshu Singh 7 years, 1 month ago

Oye ye computer h science nhi!!!!
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