Calculate the Al ions in 0.051g …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Jyoti Aggarwal 7 years, 1 month ago
- 1 answers
Test
Related Questions
Posted by Anmol Kumar 1 year, 8 months ago
- 0 answers
Posted by Himanshi Sharma 1 year, 8 months ago
- 0 answers
Posted by Yash Dwivedi 1 year, 8 months ago
- 3 answers
Posted by Moksh Bhatia 1 year, 8 months ago
- 0 answers
Posted by Prasanna Mendon 8 months, 2 weeks ago
- 1 answers
Posted by Huda Fatima 1 year, 8 months ago
- 2 answers
Posted by Op Garg 1 year, 8 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 7 years, 1 month ago
Molecular weight of Al2O3 = 102 g
102 g of Al2O3 contains 6.022X1023 molecules
0.051g of Al2O3 contain X number of molecules
X = 0.051 X 6.022X1023 /102 = 0.003 X 1020
X = 3 X 1020
1 molecule of Al2O3 contains – 2 Al+3ions
3 X 1020 molecules contains – 2 X 3 X 1020
= 6 X 1020 Al+3 ions
∴0.051 g of Al2O3 contains 6 X 1020 Al+3 ions
0Thank You