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X^2-(x+2)(x+3)÷7x+1=2÷3

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X^2-(x+2)(x+3)÷7x+1=2÷3
  • 1 answers

Aanya Singh 7 years, 1 month ago

Question : x^2 -(x+2)(x+3)÷(7x+1) = 2÷3 Answer : by cross multyplying we get, 3×(x^2-(x+2)(x+3))=(7x+1)×2 Solving the equation inside the bracket We get, 3×(x^2 - ( x^2 + 5x + 6 ) = 14x+2 3×(-5x -6 )= 14x +2 -15x - 18 = 14x + 2 -20 = 29x X = -20/29
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