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The sum of 3 consecutive multiples …

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The sum of 3 consecutive multiples of 8 is 888. Find the multiples

    • Posted by Dhriti Puri 7 years, 1 month ago

    CBSE > Class 08 > Mathematics
    • 5 answers

    Dhriti Puri 7 years, 1 month ago

    Thanks evryone for giving ur answers and time but i have already found the answer ...formula was correct only calculation were wrong

    0Thank You

    Shreya Maheshwari 7 years, 1 month ago

    Let the first consecutive number be x Second x+8 Third x+16 Sum of three consecutive numbers 888 According to question x+x+8+x+16= 888 3x+24=888 3x=888-24 3x=864 x=864/3 x= 288 1st multiple 288 2nd multiple x+8 288+8 296 3rd multiple x+16 288+16 304

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    Himanshu Garg 7 years, 1 month ago

    Thee consecutive no.= x , x+1 ,x+2 Three consecutive multiples = 8x , 8x+8,8x+16 8x+8x+8+8x+16=888 24x+24=888 24x= 888-24 24x = 864 X= 864÷24 x= 36 Required no.= 8x= 8×36 =288 8x +8 = 8×36 +8= 288 +8 = 296 8x +16 = 8×36+16= 288+16=304

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    Anjali Kumari 7 years, 1 month ago

    Let the consecutive multiples be 8x,8(x+1), 8(x+2) According to question, 8x+8(x+1)+8(x+2)=888 8x+8x+8+8x+16=888 24x+24=888 24x=888-24=864 x=864/24=36 So,all multiples are36,37,38.

    1Thank You

    Dilip Kumar 7 years, 1 month ago

    According to the question, The three consecutive number=x , x+1 , x+2. The sum of 3 consecutive multiples of 8 = 8(x+x+1+x+2) First multiple =8x Second multiple = 8(x+1) Third multiple=8(x+2) =8x+8x+8+8x+16 Now , the expression is 8x+8x+8+8x+16=888 24x+24=888 24x=888-24 24x=864 x=864/24 Hence , x=36 First multiple = 8x = 8×36 = 288. Second multiple = 8(x+1)=8×(36+1)=8×37=296. Third multiple = 8(x+2)=8×(36+2)=8×38=304. Hence , the multiples are 288 , 296 , 304 .

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