Describe rutherford experiment?

Rutherford’s Scattering Experiment:

Rutherford selected a gold foil as he wanted a very thin layer. The gold foil used by Rutherford was 0.004 millimetres  in thickness.  That is, the foil  was about 1000 atoms thick. In his experiment, fast moving α-particles (alpha particles) were made to fall on a thin gold foil. The α-particles are helium ions with a⁺² charge. Their atomic mass is  4  u.  Hence,  a  high  velocity beam of α-particles has a lot of energy.

These  particles  were  studied  by  means  of  flashes  of  light  they  produced  on  striking  a zinc  sulphide screen. The α-particles are much heavier than the sub-atomic particles present in gold atoms.

Hence, he expected the α-particles  to  pass  through  the  gold  foil  with  little  deflection  and  strike  the fluorescent screen. But the observations he made were quite unexpected.