If the radius of a sphere …

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Sia ? 6 years, 8 months ago
Let the radius of the sphere be r.
Then surface area of the sphere ={tex}4\pi r^2{/tex}
New radius of the sphere ={tex}r\over2{/tex}
∴ New surface area of the sphere ={tex}4\pi({r\over2})^2=\pi r^2{/tex}
∴ Decrease in surface area ={tex}4\pi r^2-\pi r^2{/tex}
= {tex}3\pi r^2={3\over4}{(4\pi r^2)}{/tex}
={tex}3\over4{/tex}(surface area of the original sphere).
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