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derive acceleration due to gravity

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derive acceleration due to gravity
  • 2 answers

Yashank Kumar 7 years, 2 months ago

f is directly proportional to 1/d^2.......1 F is directly proportional to Mm... ..2 From 1and 2 F is directly proportional to Mm/d^2 Directly proportional change =g Earth mass 6*10power24. (M) Earth radius 6.4*10power6. (d^2) G=6.673*10power-11 g=GMm/d^2 g=6.7*10power-11*6*10power24/(6.4*10power6)^2 g=9.8

Yogita Ingle 7 years, 2 months ago

As per Newton's law, Force = mass × acceleration = m×a .....................(1)
where m is mass and a is acceleration
Gravitational force acting on a mass m on earth's surface = G (m×M)/R2 = m × GM/R2  ..........................(2)
where G is Gravitational force constant, M is mass of earth and R is radius of earth
By comparing (1) and (2), acceleration due to gravity = a = (G×M)/R2

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