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Prove the 1/6th weight of body …

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Prove the 1/6th weight of body on moon
  • 1 answers

Gaurav Seth 7 years, 2 months ago

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The acceleration due to gravity is given by,

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g = GM/R2

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Where, M is the mass of the planet or satellite where ‘g’ is to be found and R is its radius.

For Moon,

Mm = 7.36 × 1022 kg

Rm = 1.74 × 106 m

So, gm = GMm/Rm2

For earth,

Me = 5.98 × 1024 kg

Re = 6.37 × 106 m

So,

ge = GMe/Re2

Now,

gm/ge = (Mm Re2)( Me Rm2)

Plugging in the values we get,

gm/ge = 0.16

=> ge = gm/0.16 ≈ 6gm

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