How to find CI when P=8000, …
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Posted by Isha Gupta 6 years, 5 months ago
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Sia ? 6 years, 5 months ago
By using compound interest formula
P = Rs. 8000
R = 9% p.a. {tex} = \frac{9}{2}\% {/tex} per half year
n = 1 year = 1 × 2 half years
= 2 half years
{tex}\therefore A = P{\left( {1 + \frac{R}{{100}}} \right)^n} = 8000{\left( {1 + \frac{9}{{2 \times 100}}} \right)^2}{/tex}
{tex} = 8000{\left( {1 + \frac{9}{{200}}} \right)^2} = 8000{\left( {\frac{{209}}{{200}}} \right)^2}{/tex}
{tex} = 8000 \times \frac{{209}}{{200}} \times \frac{{209}}{{200}}{/tex}
= Rs. 8736.20
{tex}\therefore {/tex} C.I. = A – P
= Rs. 8736.20 – Rs. 8000
= Rs. 736.20.
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