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ABCD is rectangle l(AB)=24cm,l(BC)=18cm. A sector …

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ABCD is rectangle l(AB)=24cm,l(BC)=18cm. A sector of radius 7cm is cut off at each corner of the rectangle . What is the area of the remaining field

Posted by Piyush Lanjewar 7 years, 2 months ago

CBSE > Class 08 > Mathematics

1 answers

Madhav Gupta 7 years, 2 months ago

Hi Student.

We can calculate the area of the rectangle by the formula L*B, Thus, 24*18 = 432.

The area of the 4 quadrant can be calculated as {22/7*7²}*4 (because there are 4 side of the rectangle and on each side a quadrant is being cut out.

The area of the all the 4 quadrant is154 cm²

For calculating the remaining area, simply. 432-154= 278cm²

^{Good luck}

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CBSE > Class 08 > Mathematics