Number of molecucules in 100g of …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sandhya Mahanty 7 years, 2 months ago
- 2 answers
Gaurav Seth 7 years, 2 months ago
M,Molar mass of NH₃=14+(1×3)=17
m,Given mass=100 g
n,number of moles=m/M=100/17
n=N/N₀
N=n×N₀=(100/17)×6.022×10²³
=3.55×10²⁴
Related Questions
Posted by Huda Fatima 1 year, 8 months ago
- 2 answers
Posted by Yash Dwivedi 1 year, 8 months ago
- 3 answers
Posted by Prasanna Mendon 8 months, 1 week ago
- 1 answers
Posted by Anmol Kumar 1 year, 8 months ago
- 0 answers
Posted by Op Garg 1 year, 8 months ago
- 2 answers
Posted by Himanshi Sharma 1 year, 8 months ago
- 0 answers
Posted by Moksh Bhatia 1 year, 8 months ago
- 0 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Gaurav Seth 7 years, 2 months ago
M,Molar mass of NH₃=14+(1×3)=17
m,Given mass=100 g
n,number of moles=m/M=100/17
n=N/N₀
N=n×N₀=(100/17)×6.022×10²³
=3.55×10²⁴
M,Molar mass of N₂=14×2=28
m,Given mass=100 g
n,number of moles=m/M=100/28
n=N/N₀
N=n×N₀
(100/28)×6.022×10²³=2.15×10²⁴
∴Number of molecules in 100 g of NH3 is more than 100 g of N2.
1Thank You