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A motorcyclist drive from AtoB with …

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A motorcyclist drive from AtoB with a uniform speed of 30 kmh and return back the speed of 20 kmh find it average speed
  • 2 answers

Kumkum Sarswat 7 years, 3 months ago

1st case let time =t1 Speed = distance /time 30km/h = d/ t1 D = 30 t1. (equation 1) 2nd case let time =t2 Speed = distance /time 20km/h = d/t2 D=20 t2. (equation 2) From equation 1 and 2 30t1= 20t2 30/20 =t2/t1 t1=2 hours t2 =3 hours Equation 2 D=20 t2 D=20 ✖ 3 D=60 km Average speed = total distance /total time S = 60 ➕ 60 /2 ➕ 3 S = 120/5 Average speed = 24 km/h Hope it will help ??

Adarsh Dubey 7 years, 3 months ago

24 km/h
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