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Determine the empirical formula of an …

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Determine the empirical formula of an oxide of iron which has 69.9℅ iron and 30.1℅ dioxygen by mass.

Posted by Ayush Bhagat 8 years, 2 months ago

CBSE > Class 11 > Chemistry

1 answers

Mansi Shrivastava 8 years, 2 months ago

Iron: % by mass= 69.9 Atomic mass= 55.85 Moles of element( relative no. of moles)= 69.9/55.85 = 1.25 Simplest molar ratio = 1.25/1.25 = 1 Simplest whole no. molar ratio= 2 Oxygen: % by mass = 30.1 Atomic mass = 16.00 Moles of element =30.1/16.00 = 1.88 Simplest molar ratio = 1.88/1.25 = 1.5 Simplest whole no. molar ratio = 3 Fe2O3

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