Derive the relation between Ka and …

Welcome ???

Thnk u??

Looks like??

My answer is correct or not

The Ka is the acid dissociation constant of a weak acid, and the Kb is the dissociation constant of its conjugate base. Alternatively, we can also say, Kb is the base dissociation constant of a weak base, and Ka is the dissociation constant of its conjugate acid. We can deduce the same relationship, i.e. Ka⋅Kb=Kw, for these cases also. Without loss of generality, let the weak acid be HA and its conjugate base is A− (you can also do the same [not identical] derivation considering base B and its conjugate acid BH+). Considering acid dissociation, HA↽−−⇀H++A−Ka=[H+][A−][HA], and for the basic action of its conjugate base, consider, A−+H2O↽−−⇀HA+OH−Kb=[HA][OH−][A−]. Multiplying both the equations, we will have, Ka⋅Kb=[A−][H+][HA]⋅[HA][OH−][A−]=[H+][OH−]=Kw So, it is proved that for any acid/conjugate base pair (or, base/conjugate acid pair) the identical relation, Ka⋅Kb=Kw holds. Hope this answer will help u??????