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How we can find out the oxidation state of Boron by using the structure of Borax . Plz ans me fast its urgent coz tommorow is my test and this ques may be come in test.So plz.

Posted by Chanchal Mudgal 7 years ago

CBSE > Class 11 > Chemistry

1 answers

[email protected] M 7 years ago

Borax is Na2B4O7. Let the oxidation state of boron be x. So, we know that the oxidation state of Sodium and Oxygen are respectively +1 and -2. So, {2×(+1)+4×(x) +7×(-2)} =0 =>2+4x-14=0 =>4x-12=0 =>4x=12 =>x=12/4 =>x=3 So, the oxidation state of boron in a molecule of borax is +3.

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