Divide 184 into 2 parts so …

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Divide 184 into 2 parts so that one-third of one part exceeds the one-seventh of the other part by 8

Posted by Naren S 6 years, 5 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Let one part = <m:omath><m:r>x</m:r></m:omath>
Then, the other part = 184 – <m:omath><m:r>x</m:r></m:omath>
One-third of the first part {tex} = \frac{1}{3}x = \frac{x}{3}{/tex}
One-seventh of the other part {tex} = \frac{1}{7}(184 - x){/tex}
According to the problem, {tex}\frac{x}{3} = \frac{1}{7}(184 - x) + 8{/tex}
{tex}\frac{x}{3} - \frac{1}{7}(184 - x) = 8{/tex}
{tex}\frac{{7x - 552 + 3x}}{{21}} = 8{/tex}
{tex}10x - 552 = 8 \times 21{/tex}
10x = 168 + 552 = 720
{tex}x = \frac{{720}}{{10}} = 72{/tex}
Hence, the first part is 72 and the second part is (184 – 72) = 112

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