Find the angel which is twice …

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Posted by Suhani Jaiswal 6 years, 5 months ago
- 1 answers
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Sia ? 6 years, 5 months ago
Let the measure be {tex}{x^0}{/tex}
Then its supplement is {tex}{180^0} - {x^0}{/tex}
According to the question
{tex}{x^0} = 2\left( {{{180}^0} - {x^0}} \right){/tex}
{tex}{x^0} = {360^0} - 2{x^0}{/tex}
{tex}3x = {360^0}{/tex}
{tex}x{\text{ }} = {120^0}{/tex}
Therfore the other angle is {tex}180^\circ - 120^\circ = 60^\circ{/tex}
The measure of the angles are {tex}{120^0} {/tex} and {tex}{60^0}{/tex}respectively.
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