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why in NaBH4 oxidation no of …

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why in NaBH4 oxidation no of B is -3
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Pragati Gola 7 years, 2 months ago

Let the oxidation number of B in NaBH4 is x then, oxidation number of Na+oxidation number of B+oxidation number of H=net charge on NaBH4 =1+x+(-1)4=0 =x-4+1=0 x=+3
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