Suppose 2kg of sugar cintains 9×10 …

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Sia ? 6 years, 5 months ago
Let the number of sugar crystals in 5 kg of sugar be x.
The given information in the form of a table is as follows.
Amount of sugar (in kg)
2
5
Number of crystals
9 × 106
x
The amount of sugar and the number of crystals it contains are directly proportional to each other. Therefore, we obtain
{tex}\frac{2}{{9 \times {{10}^6}}} = \frac{5}{x}{/tex}
{tex}x = \frac{{5 \times 9 \times {{10}^6}}}{2} = 2.25 \times {10^7}{/tex}
Hence, the number of sugar crystals is 2.25 × 107.
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