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A train starting from rest attains …

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A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (a) the acceleration (b) the distance traveled by the train for attaining this velocity.

Posted by Balwant Singh Bangari 7 years, 5 months ago

CBSE > Class 09 > Science

2 answers

Neel Shah 7 years, 5 months ago

u=0m/s v=72 km/h or 20 m/s t=5 min or 300 seconds (a) a= v-u/t a=20-0/300 a=1/15m/s (b)s=ut +1/2 at^2 s= 0*300 + 1/2*1/15*300*300 s=0 + 3000 s= 3000m or 3 km.

Neel Shah 5 years, 11 months ago

u=0m/s v=72km/h or 20m/s t=5 min or 300 seconds (a) a=v-u/t a=20-0/300 a=1/15 m/s (b)s=ut +1/2 at^2 s=0*300 +1/2*1/15*300 s=0+10 s=10 meter.

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