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A ball thrown up vertically returns …

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A ball thrown up vertically returns to the thrower after 6 seconds find the velocity with which it was thrown up

Posted by Noborup Banerjee 7 years, 6 months ago

CBSE > Class 09 > Science

4 answers

Jp Soni 7 years, 6 months ago

{1.},,,,,,,,,,,,,,Here given ....time in reaching at max height t=3sec.(here 6 sec. For the both downward and upward ) And accelaration a=-9.8m/s2(- appera because of upward motion agains gravity) and final velocity at height is v=0.......{2.},,,,,,,,,, now to be found initial velocity u=?{3.},,,,,,,,,,,, Using first equatiin of motion (because we have the quantities a,v,t ,u?) So v=u+at now putting the values we have 0=u-9.8×3,,,,,,,,,,,,so u=9.8×3=29.4m/s

Sushant Kumar 7 years, 6 months ago

58.8m/s v=u+at v will be 0 at the highest point so,0=u+9.8×6 u= --58.8m/s

Anshika Prakash 7 years, 6 months ago

First of all acceleration is -9.8m/s2. Answer- 29.4m/s

Naveen Singh 7 years, 6 months ago

Sorry, but without acceleration how it can be Found.

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