Diagonal AC of rhombus ABCD is …

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Sia ? 6 years, 5 months ago
In triangle ABC,
AB = BC = AC
∴ ∠CAB = ∠ B = ∠BCA = 60°.........(i)
Similarly ΔADC is an equilateral triangle,
∴ ∠DAC = ∠ D = ∠DCA = 60°...........(ii)
From (i) and (ii) we get
∠A = ∠ DAC + ∠CAB = 60° + 60°
∠A = ∠ DAC + ∠CAB = 120°
Similarly ∠C = 120°
Hence, ∠A = 120°, ∠B = 60°, ∠C = 120° and ∠D = 60°.
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