A polygon has 27 diagonals .how …
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Posted by Khushi Agrawal 6 years, 11 months ago
- 5 answers
Sonali Aggarwal 6 years, 11 months ago
no of diagonals= n(n-3)/2
27=n^2-3n/2
54=n^2-3n
n^2-3n-54
n^2-9n+6n-54
n(n-9)+6(n-9)
(n-9)(n+6)
n=9,-6 -6 is not possible so 9 is the answer.
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Harshit Srivastava 6 years, 11 months ago
1Thank You