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Steps for balancing chemical equations

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Steps for balancing chemical equations

Posted by Khushi Jain 7 years, 5 months ago

CBSE > Class 11 > Chemistry

4 answers

Nishita Tomar 7 years, 5 months ago

Aapko feel ni hota kya ki aapka time waste hota h itna type krne m...........@nancy

Nancy Rajput 7 years, 5 months ago

The balanced reaction is Ba (OH)2 + 2 NH4Cl ----------> BaCl2 + 2 NH3 + 2H2O Given reaction is as under:- Ba(OH)2+NH4Cl---->BaCl2+NH3+H2O As two chlorine atoms are present on the right hand side so multiply NH4Cl by 2 for getting equal number of Cl atoms on both the sides. reaction becomes Ba(OH)2+2NH4Cl---->BaCl2+NH3+H2O Now on the left side two nitrogen atoms are present so multiply NH3 by 2. Now the reaction will be Ba(OH)2+2NH4Cl---->BaCl2+2NH3+H2O. 10 Hydrogens are present on the left hand side so multiply H2O by 2 on the right hand side. Ba(OH)2+2NH4Cl---->BaCl2+2NH3+2H2O. Oxygens are equal on both the sides.

Nancy Rajput 7 years, 5 months ago

and next wait i answer you

Nancy Rajput 7 years, 5 months ago

First step : Write down the chemical reaction in the form of a word equation, keeping the reactant on the left side and the products on the right side. Second step : Put the symbols and formulae of all the reactants an the products in the word equation.

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