If 0.5mole of BaCl2 is mixed …

3BaCl2 + 2Na3PO4 -------------> Ba3(PO4)2 + 6Nacl 0.5 mol 0.20 mol x mol ⏩ ⏩ limiting reagent 0.5/3 = 1/6 0.2/2 = 1/10 1/10 < 1/6 thus, Na3PO4 is the limiting reagent. Now, 1/10 = x/1 x = 0.1 mol.

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