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Find Molality of 30 % w/w …

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Find Molality of 30 % w/w h2so4 Give with solution

Posted by Raj Goyani 7 years, 6 months ago

CBSE > Class 11 > Chemistry

4 answers

Ʌɐpɐʎ Ɐuɐɥsɹɐp . 7 years, 6 months ago

H2SO4= 98 weight of 30% of H2SO4 soln = 1.218 g = 1000 ml * 1.218 g/ml =1.218g (v*d) wt. of H2SO4 (solute) = 1218*30/100 = 365.4 g wt. of H20 (solvent) = 1218-365.4 now , total wt. of H2SO4 = 365.4+1127 = 1492.4 g 70% of H2SO4 SOln = 1000 ml * 1.61 g/cc =1610g wt. of H2SO4 (solute) = 1610*70/100 = 1127 g wt. of H2O (solvent) = 1610-1127 = 483 g now, tota wt. of H2O (Solvent)= 852.6 + 483 = 1335.6 g finalllllyyyy, molarity = wt*100/molecular wt.* wt. of solvent = 1492.4*1000/98*1335.6 = 11.4

Aman Kumar 7 years, 6 months ago

Molality= 30 ×1000/98× 100 =300/98= 3.061 Ans...

Ʌɐpɐʎ Ɐuɐɥsɹɐp . 7 years, 6 months ago

11. 4

Kushal Prajapat 7 years, 6 months ago

75÷7 of water

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