A scooter was bought at ₹42000.its …
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Rashmi Bajpayee 8 years, 3 months ago
Value of depretiation = {tex}{\rm{P}}{\left( {1 - {r \over {100}}} \right)^t}{/tex}
= {tex}42000{\left( {1 - {8 \over {100}}} \right)^2}{/tex}
= {tex}42000{\left( {{{100 - 8} \over {100}}} \right)^2}{/tex}
= {tex}42000{\left( {{{92} \over {100}}} \right)^2}{/tex}
= {tex}42000 \times {{92} \over {100}} \times {{92} \over {100}}{/tex}
= Rs.35,548.80
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